Question

1. If x + y = 12 and xy = 32, Find the value of x2

+ y2

.

Answer 1

HEYY...
X + Y = 12
XY = 32
WE KNOW THAT
(X +Y)^2 = X ^2 + Y^2 + 2XY
SO, PUTTING THE VALUES
$(12) {}^{2} = x {}^{2} + y {}^{2} + 2xy \\ 144 = {x}^{2} + {y}^{2} + 2 \times 32 \\ x {}^{2} + {y}^{2} = 144 - 64 \\ {x}^{2} + {y}^{2} = 80$

Answer 2

Heya!✋

You have asked a good question.Here is your answer.
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Given that, x + y = 12
xy = 32

The given equation,
x²+y²
=> (x+y)²- 2xy
=> (12)²-(2×32) [ By giving the value]
=> 144- 64
=> 80
[ Answer]
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Friend, I hope you can solve such type of question. :)