Question

1) If x+y =2 and xy=1 then find x^4+x^4​

Answer 1

Answer:

(4-y^4)+(4-y^4)

Step-by-step explanation:

Answer 2

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⏭ If x+y =2 and xy=1 then find x^4+y^4..✏

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✳x^4+y^4=2

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✔GIVEN...

✏x+y=2

✏xy=1

✔TO FIND...

✏x^4+y^4

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$: \large{ \sf{ \implies{x + y = 2}}} \\ \sf{ \purple{ \underline{squaring \: both \: sides}}} \\ \\ : \large{ \sf{ \implies{(x + y) {}^{2} = 4}}} \\ \\ : \large{ \sf{ \implies{ {x}^{2} + 2xy + {y}^{2} = 4}}} \\ \\ : \large{ \sf{ \implies{ {x}^{2} + {y}^{2} + 2(1) = 4}}} \\ \sf{ \green{ \underline{given \: xy = 1}}} \\ \\ \large{ \sf{ \implies{ {x}^{2} + {y}^{2} = 2}}}..........(1) \\ \sf{ \purple{ \underline{squaring \: both \: sides}}} \\ \\ : \large{ \sf{ \implies{ { ({x}^{2} })^{2} + 2 {x}^{2} {y}^{2} + { ({y}^{2} })^{2} = 4}}} \\ \\ : \large{ \sf{ \implies{ {x}^{4} + 2(xy) {}^{2} + {y}^{4} = 4}}} \\ \\ : \large{ \sf{ \implies{ {x}^{4} + 2(1) {}^{2} + {y}^{4} = 4}}} \\ \sf{ \green{ \underline{given \: xy = 1}}} \\ \\ \large{ \sf{ \implies{ \red{ \boxed{ {x}^{4} + {y}^{4} = 2}}}}}$

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