Question

1 If x - y = 8 and xy = 5, find x2 +

Answer 1

GIVEN:

x-y = 8

xy = 5

________

TO FIND:

x²-y²

_________

HOW TO SOLVE?

$x - y = 8 \\ (x - y) {}^{2} = ( {8)}^{2} \\ {x}^{2} + y {}^{2} - 2xy = 64 \\ pu t \: value \: of \: xy \: that \: is \: given \\ {x}^{2} + {y}^{2} - 2(5) = 64 \\ {x}^{2} + {y}^{2} - 10 = 64 \\ {x}^{2} + {y}^{2} = 64 + 10 \\ {x}^{2} + {y}^{2} = 74$

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Answer 2

we don't get 250 we get 265