Question

1. if x+y+z=8 and xy+yz+zx=20,find the value of x^3+y^3+z^3-3xyz. 2. if a+b+c=9 and a^2+b^2=c^2=35,find the value of a^3+b^3+c^3-3abc pls do it fast.....it is very important......

Answer 1

Step-by-step explanation:

(x+y+z)^2=x^2+y^2+z^2+2(xy+yz+zx)

X^2+y^2+z^2=(8)^2-2(20)

=64-40

=24

x^3+y^3+z^3-3xyz=(x+y+z)(x^2+y^2+z^2-xy-yz-zx)

=(8)(24-20)

=8*4

=32