Question

+ 1
If x1 = -1 and Xm = Xm
+ (m + 1) for every
positive integer m,
then X100 equals
A. -5050
B. -5051
C. -5150
D. -5151​

Answer 1

Answer:

y

. If x(base 1) = -1 and x(base m) = x(base m+1) + (m+1) for every positive integer m, then x(base 100) equals?

-5051

-5151

-5050

-5150

Answer: 3

Solution:

X2 = x1 – (1+1) = -1 -2 = -3

X3 = x2 –(2+1) = – 6

X4 =x3 – (3+1) = -10

….so on

So x100 = – (1+2+3+4+…+100) = – 100/2 (1+100) = – 5050

Step-by-step explanation:

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