Question

1. If x3 + 6x2 + 4x + k is exactly divisible by x + 2, then find the value of k.​

Answer 1

hope this answer will be helpful

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Answer 2

Answer:

$x + 2 = 0 \\ x = - 2 \\ - 2(3) + 6( - 2)2 + 4( - 2) + k = 0 \\ - 6 - 24 - 8 + k = 0 \\ - 30 - 8 + k = 0 \\ - 38 + k = 0 \\ k = + 38 \\ proved.$