Question

1. If xcosθ – ysinθ = a, xsinθ + ycos θ = b, prove that x2+y2=a2+b2.

Answer 1

Hre u go see the answer and mark brainliest

Answer 2

Answer:

step by step explanation

xcosθ−ysinθ=a......(1)

xsinθ+ycosθ=b.....(2)

(1)2+(2)2

(xcosθ−ysinθ)2+(xsinθ+ycosθ)2=a2+b2

x2cos2θ+y2sin2θ−2xysinθcosθ+x2sin2θ+y2cos2θ+2xycosθsinθ=a2+b2

x2(cos2θ+sin2θ)+y2(sin2θ+cos2θ)=a2+b2

x2+y2=a2+b2

hope u understood .