Question

1 If y = 4a² + b2 - 6ab; y = 3b 2 - 2a2 +
8ab and z= 6a2 + 8b2 - 6
ab, find
X - Y - Z
​

Answer 1

Answer:

hi,

given,

x = 4a²+b²-6ab

y = 3b²-2a²+8ab

z = 6a²+8b²-6

now, x-y-z = 4a²+b²-6ab - (3b²-2a²+8ab) - ( 6a²+8b²-6)

x-y-z = 4a²+b²-6ab - 3b²+2a²-8ab - 6a²-8b²+6

x-y-z = 4a²+2a²-6a²+b²-3b²-8b²-6ab-8ab+6

x-y-z = -10b²-14ab+6

pls mark as brainliest