1 If y = 4a² + b2 - 6ab; y = 3b 2 - 2a2 +
8ab and z= 6a2 + 8b2 - 6
ab, find
X - Y - Z
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Answer:
hi,
given,
x = 4a²+b²-6ab
y = 3b²-2a²+8ab
z = 6a²+8b²-6
now, x-y-z = 4a²+b²-6ab - (3b²-2a²+8ab) - ( 6a²+8b²-6)
x-y-z = 4a²+b²-6ab - 3b²+2a²-8ab - 6a²-8b²+6
x-y-z = 4a²+2a²-6a²+b²-3b²-8b²-6ab-8ab+6
x-y-z = -10b²-14ab+6
pls mark as brainliest
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