Question

1.if y=sec^-1(1+x^2/1-x^2) then dy/dx=?
2.y=cot^-1{√(1+cosx/1-cosx)} then dy/dx=?

Answer 1

Answer:

y=1+cosx1−cosx ⇒y=1+cosx1−cosx ×1−cosx1−cosx =1− cos2x 1−cosx=sinx1−cosx=cscx−cotx. ∴dxdy=tan(2x)cscx = cos2x(2sin(2x)cos(2x))sin(2x) =21sec2(2x). Answered By.

Answer 2

Answer:

Can't understand soory