Question

1 If zerous of( P)=2x²-7x+k are reciprocal
of each other, then find the value of k.​

Answer 1

Given:

• p(x) = 2x² - 7x + k
• Zeroes of the polynomial are reciprocal of each other.

To Find:

• Value of k.

Solution:

Let the one zero be α.

• p(x) = 2x² - 7x + k ---(i)

As we know:

★Sum of zeroes = -b/α

→ α + 1/α = -(-7)/2

→ α² + 1/α = 7/2

→ 2(α² + 1) = 7α

→ 2α² + 2 = 7α

→ 2α² - 7α + 2 = 0 ---(ii)

On comparing (i) & (ii), we get;

→ k = 2

Hence,

• Value of k = 2

Answer 2

Answer:

If zerous of( P)=2x²-7x+k are reciprocal

of each other, then the value of k is 2

Step-by-step explanation:

hope it helps you

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