. 1) Ifa+b=5 and a-b=13, the value of (a+ba) is (a) 8 (b) 4 (c) 2 (d) 1
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Answer:
Step-by-step explanation:
(a+b)^2= a^2+b^2+2ab
Putting the value of a+b and ab we get,
a^2+b^2=25–6
a^2+b^2=19 *
Now,
(a-b)^2= a^2+b^2–2ab
Putting the value of a^2+b^2=19
We get, (a-b)^2=19–6
a-b= √13, -√13
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