1) Ifp= 21/3+ 2_1/3, show that 2p3 - 6p = 5
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Let the first odd number be x and the next odd number be (x + 2)
x(x+2) = 255x(x+2)=255
\Rightarrow x^2 + 2x = 255⇒x2+2x=255
\Rightarrow x^2 + 2x + 1 = 255 + 1⇒x2+2x+1=255+1
\Rightarrow (x+1)^2=256⇒(x+1)2=256
\Rightarrow x+1=\sqrt{256}=16⇒x+1=256=16
\Rightarrow x = 16-1 = 15⇒x=16−1=15
The next consecutive odd number = 15 + 2 = 17
Hope it helped
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