Question

(1)
Ifp(x)=x2-5x-6, then find the values of p(1), p(2),p(3),p(0),p(-1),p(-2), p(-3).
If p(m) = m2 - 3m+ 1, then find the value of p(1) and p(-1).​

Answer 1

Step-by-step explanation:

$\sf\huge\underline\red{Answer:-}$

p(x) = x²-5x -6

Putting p value is 1

p(1) = (1)²-5-6

p(1)= 1-11

p(1) = -10

Putting p value is 2

p(2) = (2)²-10-6

p(2) = 4 -26

p(2) = -22

Putting p value is 3

p(3) = (3)²-15-6

p(3) = 9-21

p(3) = -12

Putting p value is 0

p(0) = 0-0-6

p(0) = -6

Putting p value is -1

p(-1) = (-1)²+5-6

p(-1) = 1 -1

p(-1)=0

Putting p value is -2

p(-2) = (-2)²+10-6

p(-2) = 4+10-6

p(-2) = 8

Putting p value is -3

p(-3) = (-3)³+15-6

p(-3) = 9 +15-6

p(-3)=18

p(m) = m²-3m+1

Putting m value is 1

p(1) = (1)²-3+1

p(1)=1-3+1

p(1)=-1

Putting m value is -1

p(-1) = (-1)²+3+1

p(-1)= 1+3+1

p(-1)= 5

Hope it will help you mate !!

Answer 2

p(x)=x2-5x-6 sol:

-9,-12,-15,-6,-3,0,3

p(m)=m2-3m+1

0,2

Step-by-step explanation:

p(x)=x2-5x-6

p(1)=(1)2-5(1)-6

=2-5-6

=-9

p(2)=(2)2-5(2)-6

=4-10-6

=-12

p(3)=(3)2-5(3)-6

=6-15-6

=-15

p(0)=(0)2-5(0)-6

=-6

p(-1)=(-1)2-5(-1)-6

=-2+5-6

-3

p(-2)=(-2)2-5(-2)-6

=-4+10-6

=0

p(-3)=(-3)2-5(-3)-6

-6+15-6

=3

p(m)=m2-3m+1

p(x)=1,-1

p(1)=(1)2-3(1)+1

=2-3+1

=0

p(-1)=(-1)2-3(-1)+1

-2+3+1

=2