Question

1.Ifsinα=
√3
2

and cosβ=0,then the bvaluebof β–α is

a)00

b)90
0

c)60
0

d)300

​

Answer 1

Answer:

sina=√3/2

sina=sin60

a=60

cosb=0

cosb=cos90

b=90

b-a=90-60=30

option d is correct