Question

1) Ifx = a sin 0, y = b tan 0,
a?
then Prove that:a2/x2-b2/y2=1​

Answer 1

Let's solve for a.

$→a^2x−b^2y2=1$

$Step 1: Multiply\; both \;sides by \;x^2y^2.$

$a2y2−b2x2=x2y2$

$Step 2: Add b^2x^2 to both sides.$

$a2y2−b2x2+b2x2=x2y2+b2x2$

$a^2y^2=b^2x2^2+x^2y^2$

$Step 3: Divide \;both \;sides \;by y^2.$

$a2y2y2=b2x2+x2y2y2a2=b2x2+x2y2y2$

→Step 4: Take square root.

$a=√b2x2+x2y2y2 or a=−√b2x2+x2y2y2$

$Answer:$

→a=√

$b2x2+x2y2$

$y2 or a=−√b2x2+x2y2y2$