Question

1.
ii
.
i. (x + 1)2 = 2(-3)
j. (x - 2)(x + 1) = (x - 1)(x + 3)
(2x - 1)(x-3) = (x + 5)(x - 1)
vii. (x + 2)2 = 2x (x2 - 1)
Renrecanto
Check whether the following are quadratic equations:
x² – 2x=(-2) (3 - x)
(x - 3)(2x +1) = x(x + 5)
iv.
x2 + 3x + 1 = (x - 2)2
x2 - 4x2 - x + 1 = (x - 2)3
undmatic equations
V.
vi.
viii
.​

Answer 1

Step-by-step explanation:

i)

(x+1)

2

=2(x−3)

x

2

+2x+1=2x−6

x

2

+7=0 → Quadratic

ii)

x

2

−2x=−2(3−x)

x

2

−2x=−6+2x

x

2

+4x+6=0 → Quadratic

iii)

(x−2)(x+1)=(x−1)(x+3)

x

2

−x−2=x

2

+2x−3

3x=1 → Non Quadratic

iv)

(x−3)(2x+1)=(x)(x+5)

2x

2

−5x−3=x

2

+5x

x

2

+10x−3=0 → Quadratic

v)

(x−3)(2x−1)=(x−1)(x+5)

2x

2

−7x+3=x

2

+4x−5

x

2

−11x+8=0 → Quadratic

vi)

x

2

+3x+1=(x−2)

2

x

2

+3x+1=x

2

−4x+4

7x=3 → Non Quadratic

vii)

(x+2)

3

=2x(x

2

−1)

x

3

+8+6x(x+2)=2x

3

−2x

x

3

+8+6x

2

+12x=2x

3

−2x

−x

3

+6x

2

+14x+8=0 → Non Quadratic

viii)

x

3

−4x

2

−x+1

=x

3

+3x

2

(−2)+3x(−2)

2

+(−2)

3

x

3

−4x

2

−x+1=x

3

−6x

2

+12x−8

x

3

−4x

2

−x+1−x

3

+6x

2

−12x+8=0

2x

2

−13x+9=0 → Non Quadratic