1. In A ABC, right-angled at B, AB = 24 cm, BC = 7 cm. Determine :
(i) sin A, cos A
(i) sin C, cos C
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Answer:
Given triangle ABC
B=90°,AB=24cm,BC=7cm
- sinA=opposite side to A/ hypotenuse
- AC=?
- AC= √(AB square+BC square) ( by pytogorean relation)
- √(24 square +7 square)
- √(576+49)
- √(625)
- 25
- therefore AC=25cm
- sin A=7/25
- cosA=adjacent side to A/hypotenuse
- cos A=24/25
- sin C= 24/25
- cos C=7/25
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