1. In A ABC, right-angled at B, AB = 24 cm, BC= 7cm. Determine:
(i) sin A, cos A
(ii) sin C, cos C
please send me the answer quickly
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Answer:
(i a) sinA = 7/25
(i b) cosA = 24/25
(ii a) sinC = 24/25
(ii b) cosC = 7/25
Step-by-step explanation:
Given a right triangle ABC right angled at B => hypotenuse is AC
also given AB = 24cm, and BC=7cm
By pythogorean theorem,
AC² = AB² + BC²
=> AC² = 24²+7²
=> AC² = 576+49
=> AC²=625
=> AC=√625 = 25cm
Now,
Take the angle is at A => opposite side is BC and adjacent side is AB
so, (i) sinA = opp/hyp = BC/AC = 7/25
(ii) cosA = adj/hyp = AB/AC = 24/25
Taking the angle at C implies opposite side is AB and adjacent side is BC
so, (i) sinC = opp/hyp = AB/AC = 24/25
(ii) cosC = adj/hyp = BC/AC = 7/25
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