Question

1. In a club of 200 members 140 play cricket, *160 play foot ball. How many
play both the cricket and football?

O 20
ON
O40
O Cannot be determined​

Answer 1

Given:

Members playing cricket, n(c)= $140$

Members playing football, n(f)=160

Total members,n(c∪f) = $200$

To Find:

Members playing both cricket and football, n(c∩f)

Solution:

n(c∪f)=n(c)+n(f)-n(c∩f)

$200=140+160$ -n(c∩f)

n(c∩f)= $140+160-200$

         =$100$

Hence the number of players playing both cricket and football is 100.

Answer 2

Step 1: Given data

$C$∪$F=200$

$C=140$

$F=160$

$C$∩$F=?$

Step 2: Using the formula

$C$∩$F=C+F-C$∪$F$

Step 3: Calculating $C$∩$F$

$C$∩$F=140+160-200$

$C$∩$F=300-200$

$C$∩$F=100$

Hence, the number of memebers who play both cricket and football is $100$.

Note: None of the given options are correct.

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