Question

1. In a food safety drive a team of food inspectors collected samples
of adulterated 420 pieces of burfis and 148 pieces of laddoos.
They want to pack these pieces in such a way that each pack has
the same number of pieces of sweets. What is the maximum
number of sweets pieces that can be placed in each pack? kindly answer ASAP.

Answer 1

Answer:

Step-by-step explanation:

Let maximum no. of sweets in one packet be = x

let no. of packets be = a

∴ 420 = ax

148 = ax

∴ x is a common factor of 420 and 148

x is a HCF of 420 and 148

therefore, 420 = 2×2×3×5

148 = 2×2×37

HCF = 2x2 = 4

therefore, maximum no. of sweets that can be packed equally = 4.

Answer 2

Given :  In a food safety drive a team of food inspectors collected samples

of adulterated 420 pieces of burfis and 148 pieces of laddoos.

To find :  maximum  number of sweets pieces that can be placed in each pack so that each pack has  the same number of pieces of sweets.

Solution:

420 pieces of burfis and 148 pieces of laddoos.

We need to find HCF of both to get maximum number of sweet pieces that can be  put so that each pack has  the same number of pieces of sweets.

148  = 2 * 2 * 37

420 = 2 * 2 * 3 * 5 * 7

HCF = 2 * 2 = 4

4 pieces of Sweet can be put in each pack.

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