Question

1. In a Laboratory, the count of bacteria in a certain experiment was increasing at the rate of 2.5% per hour. Find the bacteria at the end of 2 hours if the count was initially 5, 06,000.​

Answer 1

Answer:

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Step-by-step explanation:

growth in 1 hour- 2.5%

growth in 2 hours- 2.5*2=5%

5% of 506000=531300

Answer 2

We need to learn the concept of percentages to solve these questions. It is a direct question on percentage.

SOLUTOIN:

$\begin{array}{l}{Increase=2}{.5\%of506000} \\ {Increase=}\frac{{{2}{.5}}}{{{100}}}{\times506000} \\ {Increase=2}{.5\times5060} \\ {Increase=126500} \\ {{HenceIncreasein2hours=2}}\times{126500} \\ {{Increasein2hours}}=253000\end{array}</p><p></p><p>\begin{array}{l}{Total}\, {Count=Initial+Increased} \\ {Total}\, {Count=506000+253000} \\ {Total}\, {{Count=759000}}\end{array}</p><p></p><p>[tex]\begin{array}{l}{Total}\, {Count=Initial+Increased} \\ {Total}\, {Count=506000+253000} \\ {Total}\, {{Count=759000}}\end{array}$[/tex]

The total count of bacteria ta the end of 2 hours is 759000.✅