1. In a mental ability test of tribal youth of 18 years age the mean = 105 and standard deviation 12. of a sample of 100 were drawn from population, what is the probability of having a mean that would differ from population mean by 3 points
Answers
Given : In a mental ability test of tribal youth of 18 years age
the mean = 105 and standard deviation 12.
a sample of 100 were drawn from population
To Find : the probability of having a mean that would differ from population mean by 3 points
Solution:
Mean = 105 SD = 12 , n = 100
SE = SD/√n = 12/√100 = 1.2
mean that would differ from population mean by 3 points
Z score = ± 3/ SE
= ± 3 / 1.2
= ± 2.5
Probability of having a mean that would differ from population mean by maximum 3 points only
= 0.9938 - 0.0062 = 0.9876
Probability of having a mean that would differ from population mean by more than 3 points = 1 - 0.9876 = 0.0124
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