Question

1) In a parallelogram ABCD, diagonals AC and BD intersect at O and AC = 12.8cm, BD = 7.6cm then find the measures of OC and OD. 2) In the given figure, find the values of x and y [ refer to Fig]​

Answer 1

Answer:

x=105° and y=105°

Step-by-step explanation:

1)x+75°= 180°.........(angles in linear pair)

:. x= 180°-75°

:.x= 105°

2) y=angle 105°........(vertically opposite angles)

:.y=105°

Answer 2

Answer:

1) now parallelogram triangle AOB will be congruent to Triangle DOC by S.A.S criteria

OD = OB = 1/2 (BD)

AO = OC = 1/2(AC) these both can be concluded by CPCT

as AC is 12.8 then OC will be 6.4

BD is 7.6 then OD will be 3.8

2) y = 105° ( by vertically opposite angle)

x = 105° ( by corresponding angles)