Question

1.
In a photosynthesis experiment, a plant is left in bright sunlight for several hours. A leaf is then
removed from the plant and tested for starch, using iodine solution. The diagram shows the leaf
from the plant that was used in the experiment
white area
green area
Which diagram shows the result of the experiment?



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Answer 1

Answer:

diagram c is the correct answer

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Answer 2

Diagram C shows the result of the experiment.

• When the plant is left in the bright sunlight for several hours, the parts of the leaf where chlorophyll is present conduct photosynthesis.
• As photosynthesis is conducted, the glucose formed during photosynthesis is stored in the form of a polysaccharide, starch.
• Now, it is given that the leaf from the plant that was used in the experiment had white and green areas.
• The white area of the leaf is devoid of chlorophyll, so no photosynthesis might have occurred and consequently, no starch is present here.
• Hence, when tested with iodine, the part of the leaf that was initially green will turn blue/black. While the part that was initially white will show no change in iodine colour, i.e., it will remain brown.