Question

1. In a public examination 90% students passed and 8800 students failed
How many students appeared and how many passed?​

Answer 1

Answer:

i).88,000. ii).79,200

Step-by-step explanation:

Let total no. of students be x

No. of students who passed = 90/100 of x

No. of student who failed=8800

So A.T.Q:

90/100x+8800=x

9x/10+8800=x

8800=x-9x/10

8800=10x-9x/10

8800×10=x

88,000=x

Total No. of students =88,000

No. of students who passed:

=90/100×x

=90/100×88000

=90×880

=79,200

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