1. In a public examination 90% students passed and 8800 students failed
How many students appeared and how many passed?
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Answer:
i).88,000. ii).79,200
Step-by-step explanation:
Let total no. of students be x
No. of students who passed = 90/100 of x
No. of student who failed=8800
So A.T.Q:
90/100x+8800=x
9x/10+8800=x
8800=x-9x/10
8800=10x-9x/10
8800×10=x
88,000=x
Total No. of students =88,000
No. of students who passed:
=90/100×x
=90/100×88000
=90×880
=79,200
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