Math, asked by aabhatkas2, 5 hours ago

1. In a pythgorean triplet two members are 8 and 10. The third member is

a) 5. b) 6. c)4. d) none of these

2. Square root of 169 is

a) 9. b)10. c)11. d)13


3. cube root of 8000 is

a)10. b)30. c)50. d) none of these


4. Which among the following numbers are perfect squares 11, 12, 16, 32, 36

a) 16,36. b)11,6 c) 12,32. d)16,32

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Answers

Answered by Armys99
29

Answer:

1) 6

2) 13

3) none of these

4) 16,32

I hope it helps you

Answered by Anonymous
87
  1. d) none of these
  2. d) 13
  3. d) none of these
  4. a) 16, 36

Proof:

  1. The given numbers are 8 and 10. To find the third number, we know that the Pythagorean Triplet has been stated as 2m, m^2 + 1 and m^2 - 1. Assume that 2m = 8 then m = 4, so m^2 + 1 = 4^2 + 1 = 16 + 1 = 17 and m^2 - 1 = 4^2 - 1 = 16 - 1 = 15. So the answer is none of these. BUT, the third member of the Pythagorean Triples of 8 and 10 is 6 because 6^2 + 8^2 = 10^2 .
  2. The square root of 169 is 13 because if we multiply 13 by itself, the product will always be 169.
  3. The cube root of 8000 is 20 because if we multiply 20 with itself for three times then the product will always be 8000.
  4. 16 and 36 are the perfect squares among the followings because the square root of 16 and 36 is 4 and 6 respectively.
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