1 in a reaction 5.3 g of sodium
carbonate reacted with 6 g of
acetic acid. The products were
2.2 9 of carbon dioxide, 090
water and 5.2 g of sodium
acetate. Show that these
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Mass of reactants = Mass of sodium carbonate + Mass of acetic acid
= 5.3 + 6 = 11.3 g
Mass of products = Mass of carbon dioxide + Mass of water + Mass of sodium acetate
= 2.2 + 0.9 + 8.2 = 11.3 g
Since the mass of products is equal to mass of reactants .
Thus observation made is in agreement with the law of conservation of mass.
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Sodium carbonate + acetic acid → Sodium acetate + carbon dioxide + water
Solution :
Sodium carbonate + acetic acid → Sodium acetate + carbon dioxide + water
5.3g 6g 8.2g 2.2g 0.9g
As per the law of conservation of mass, the total mass of reactants must be equal to the total mass of products
As per the above reaction, LHS = RHS i.e., 5.3g + 6g = 2.2g + 0.9 g + 8.2 g = 11.3 g
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