Chemistry, asked by 123456789ritka, 10 months ago

1 in a reaction 5.3 g of sodium
carbonate reacted with 6 g of
acetic acid. The products were
2.2 9 of carbon dioxide, 090
water and 5.2 g of sodium
acetate. Show that these​

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Answers

Answered by AdityaHappy
7

Mass of reactants = Mass of sodium carbonate + Mass of acetic acid

= 5.3 + 6 = 11.3 g

Mass of products = Mass of carbon dioxide + Mass of water + Mass of sodium acetate

= 2.2 + 0.9 + 8.2 = 11.3 g

Since the mass of products is equal to mass of reactants .

Thus observation made is in agreement with the law of conservation of mass.

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Answered by Anonymous
37

Sodium carbonate + acetic acid → Sodium acetate + carbon dioxide + water

Solution :

Sodium carbonate + acetic acid → Sodium acetate + carbon dioxide + water

5.3g 6g 8.2g 2.2g 0.9g

As per the law of conservation of mass, the total mass of reactants must be equal to the total mass of products

As per the above reaction, LHS = RHS i.e., 5.3g + 6g = 2.2g + 0.9 g + 8.2 g = 11.3 g

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