Question

1. In a right angled triangle ABC, angleA is acute, angleB = 90° and tan A =3/5

Find
i) sin A
ii) cosecA - cotA​

Answer 1

Answer:

I) sinA=3/5.8

ii) cosecA-cotA

5.8/3-5/3

(5.8-5)/3

0.8/3

8/30

4/15 Ans..

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Answer 2

Answer:

1⃣Sin A=3/5.8

2⃣Cosec A-CotA

=5.8/3-5/3

=(5.8-5)/3

=0.813

=8/30

=4/5

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