Question

1.In a right angled triangle Sin=5/13 Find all the
trigonometric ratios for the triangle​

Answer 1

Answer:

cosA=7/13

tanA=5/7

cotA=7/5

cosecA=13/5

secA=13/7

Step-by-step explanation:

sinA=5/13

sinA = PERPENDICULAR/HYP

=5/13

THEREFORE , P=5X, HYP=13X BASE=7X

cosA=b/h=7x/13x=7/13

tanA=p/b=5x/7x=5/7

cotA=b/p=5/7

cosec=h/p=13/5

secA=h/b=13/7

Answer 2

Given

• Sinθ = 5/13

To Calculate

• All trigonometric ratios

Step by step explanation

• Sin θ = 5/13 (Given)

We know that,

Sin θ = perpendicular/ hypotenuse

So

Perpendicular = 5

Hypotenuse = 13

By pythagoras theorem

(hypotenuse)²= (perpendicular)²+ ( Base)²

=》 (13)²= (5)²+(b)²

=》 169=25+b²

=》169-25=b²

=》144= b²

=》b = 12

Base = 12

☆ Trigonometric Ratios are ☆

Sin θ = perpendicular/hypotenuse

• Sin θ = 5/13

Cos θ = Base / hypotenuse

• Cosθ = 12/13

Tan θ = perpendicular/ Base

• Tan θ = 5/12

Cotθ = Base / Perpendicular

• Cot θ = 12/5

Secθ = Hypotenuse/Base

• Sec θ = 13/12

Cosec θ = hypotenuse/perpendicular

• Cosec θ = 13/5

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