1) In a right triangle ABC, right angled at C, if tanA=1/root3, find value oF sinA cosB+cos A sinB. 2)In a right angled triangle, right angled at A, if tanC=root 3, find value of sinBcosc+cosBsinC.
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In the given right angled triangle
tan A = 1/root 3
or, A = 30
given C = 90 .... so, A + B + C = 180
or, B = 60
Now, sinA.cosB + cosA.sinB = sin ( A + B ) = sin ( 30 + 60 ) = sin 90 = 1
Second question is similar to first one . Only when tan C = root 3 C = 60
Rest is same.
tan A = 1/root 3
or, A = 30
given C = 90 .... so, A + B + C = 180
or, B = 60
Now, sinA.cosB + cosA.sinB = sin ( A + B ) = sin ( 30 + 60 ) = sin 90 = 1
Second question is similar to first one . Only when tan C = root 3 C = 60
Rest is same.
Answered by
2
Answer:
In the given right angled triangle
tan A = 1/root 3
or, A = 30
given C = 90 .... so, A + B + C = 180
or, B = 60
Now, sinA.cosB + cosA.sinB = sin ( A + B ) = sin ( 30 + 60 ) = sin 90 = 1
Second question is similar to first one . Only when tan C = root 3 C = 60
Rest is same.
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