Question

1.In a triangle ABC,if bsinC+csinB=2
then bsinC is​

Answer 1

Given : bsinC + csinB = 2

To find : Value of bsinC

Solution :

9n a triangle,

a/csinA = b/csinB = c/csinC

bsinC = csinB

So bsinC is 1

hence answer is 1