Question

1. In a two-digit number, the units digit is 3 more than the ten's digit. The sum of the
digits is 18 less than the original number. Find the product of the digits.​

Answer 1

Answer:

Product of the digits is 10

Step-by-step explanation:

Let the digit at ten's place be x

Then the digit at unit's place = x + 3

Number = 10(x) + (x + 3) = 11x + 3

Given that sum of digits is 18 less than the original number

We have

x + (x + 3) = (11x + 3) - 18

2x + 3 = 11x + 3 - 18

11x - 2x = 18

9x = 18

x = 2

Thus, Digit at ten's place = 2

Digit at unit's place = 2 + 3 = 5

Product of digits = 2 × 5 = 10