1. In AABC, angleA - angleB = 24° and angleB - Angle C = 30°.
Find angle A.
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Answer:
angleA-angleB=24
angleB-angleac=30
triangleABC=angleA+angleB+angleC=180
24+angleB+angleB+angleB-30=180
3angleB-6=180
3angleB =180+6
angleB. =186/3
angleB=62 degrees
angleA-62=24
angleA. =24+62
=86degrees
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