Question

1. In AABC, angleA - angleB = 24° and angleB - Angle C = 30°.
Find angle A.​

Answer 1

Answer:

angleA-angleB=24

angleB-angleac=30

triangleABC=angleA+angleB+angleC=180

24+angleB+angleB+angleB-30=180

3angleB-6=180

3angleB =180+6

angleB. =186/3

angleB=62 degrees

angleA-62=24

angleA. =24+62

=86degrees