Question

(1) In AABC, BC = 3 cm, find AB.
angle A=30 AND ANGLE B =90 AND ANGLE C=60
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Answer 1

Step-by-step explanation:

AB = 2 × BC ......( side opposite to 90°)

= 2 × 3

AB = 6 cm

Answer 2

Answer:

3×sqrt3

Step-by-step explanation:

in right angled triangle abc

given it is right angled at b and bc=3

now making use of trigonometry

tanC=AB/BC (tan theta =P/B)

tan60=AB/3

AB=3×tan60

AB=3sqrt3 ( tan60=sqrt3).