Question

1. In AACB, <C = 90° and CD Perpendicular
AB

Prove that
BC square/AC square =BD/AD​

Answer 1

Step-by-step explanation:

GIVEN:- In triangle ABC

/_C =90°

CD | TO AB

TO PROVE:- (BC)2 \ (AC)2=BD\AD

PROOF:-

In triangle ABC,

AC/CB = AD/DB --------[ BY BASIC PROPRTIONALITY THM]

:. (BC)2\(AC)2 = BD\AD.

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