1) In ∆ABC, if ∠A + ∠B = 108° and ∠B + ∠C = 130°, find ∠A, ∠B and ∠C. 2) In ∆PQR, if ∠P − ∠Q = 42° and ∠Q − ∠R = 21°, find ∠P, ∠Q and ∠R.
Answers
Answered by
2
Answer:
<A=50°<B=58°<C=72°
<P=95°<Q=53°<R=32°
Step-by-step explanation:
1) <A+<B=108°
<B+<C=130°
By solving this Equation, we get <A=50° <B=58° <C=72°
2) <P-<Q= 42°
<Q-<R= 21°
By solving this Equation ,we get
<P= 95° <Q=53° <R=32°
Answered by
1
Answer:
here's your answer mate
<P = 95°
<Q = 53°
<R = 32° ...
hope it correct to u...
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