Question

1)In ∆ ABC point D on side BCis such that DC = 6, BC = 15.Find A(∆ABC): A(∆ADC)​

Answer 1

Answer:

we know that,

in similar triangles if ratios of area is equal to the ratio of squares of their corresponding sides.

ar(∆ABC)/ar(∆ADC)=(BC/DC)²

=(15/6)²

=(5/2)²

=25/4

→ar(∆ABC):ar(∆ADC)=25:4