Question

1. In ∆ ABC, right-angled at B, AB = 24 cm, BC = 7 cm. Determine:
(i) sin A, cos A
(ii) sin C, cos C​

Answer 1

Answer:

Step-by-step explanation:

In Δ ABC, right-angled at B

Using Pythagoras theorem

AC² = AB² +BC²  

AC² = 576 + 49 = 625

AC = √635

AC = ±25

AC\:=\:+ 25

Now

(i) In a right angle triangle ABC where B=90° ,

Sin A = \frac{BC}{AC}

= \frac{7}{25}

CosA = \frac{AB}{AC}

= \frac{24}{25}

ii) Sin C = \frac{AB}{AC}

= \frac{24}{25}

Cos C = \frac{BC}{AC}

= \frac{7}{25}

hope it will help you   ^_^

pls mark me brainliest