Question

1)In adjoining fig PQ 0 BC, AD BC then find following ratio A
i)
A(APQB)
A(APBC)
ii)
A(APBC
A(GABC
AAABC)
AAADC)
A(A ADC)
iv)
A(APQC)
B
Q
D C​

Answer 1

Step-by-step explanation:

In adjoining figure PQ⊥BC,AD⊥ BC then find following ratios.

(i) A(ΔPQB)/A(ΔPBC)  =  BQ/BC

(ii)A(ΔPBC)/A(ΔABC)  = PQ/AD

(iii)A(ΔABC)/A(ΔADC)  = BC/DC

(iv)A(ΔADC)/ A(ΔPQC) = (DC * AD) / (QC * QP)

Step-by-step explanation:

A(ΔPQB)  = (1/2) BQ * PQ

A(ΔPBC)  = (1/2) BC * PQ

=> A(ΔPQB)/A(ΔPBC)  = BQ/BC

A(ΔPBC) = (1/2) BC * PQ

A(ΔABC)

=  (1/2) BC * AD

A(ΔPBC)/A(ΔABC)  = PQ/AD

A(ΔABC) = (1/2) BC * AD

A(ΔADC)  = (1/2) DC * AD

A(ΔABC)/A(ΔADC)  = BC/DC

A(ΔADC) = (1/2) DC * AD

A(ΔPQC) = (1/2) QC * QP

A(ΔADC)/ A(ΔPQC) = (DC * AD) / (QC * QP)