Question

1) In an A.P. sum of three consecutive terms is 30 and their product is 360. Find
the terms.​

Answer 1

let first term be X

let second term be X +1

let 3rd term be X +2

now.. X + X +1 + X +2 =30

3x+3=30

3x= 30-3

X= 27/3

X = 9

now 1st term is 9

2nd term is 9+1=10

and 3rd term is 9+2 =11

hope it helps....

Answer 2

Answer:

30 = 3/2 (a + 2d)

a + 2d = 60/3

a + 2d = 20 --> eq 1

a1 *a2*a3= 360-->

a1= a

a2= a+d

a3= a+2d

a * (a+d) * (a+2d) = 360

a^2 + 3ad + 2d^2 = 360/a

Step-by-step explanation: