1. In APQR, PR=cm, QR= a m, PR=b mand ZR= 90°. Write down an expression for tan(P), Draw the
triangle as well.
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Answer:
Given: PQ=10cm, PR=24cm
Let QR be x cm.
In right angled triangle QPR,(Hypotenuse)2=(Base) 2+(Perpendicular) 2 [By Pythagoras theorem]
⇒(QR)2=(PQ)2+(PR)2⇒x2 =(10)2+(24)2
⇒x2
=100+576=67⇒x= 676
=26cm
Thus, the length of QR is 26cm.
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arg7990:
thank you.so much
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