Question

(1) In class 10A, there are 30 boys and 20 girls. In 10B, there are 15 boys

and 25 girls. One student is to be selected from each class. i) What is the probability of both being girls?

What is the probability of both being boys? i) What is the probability of one boy and one girl? iv) What is the probability of at least one boy​

Answer 1

Answer:

1)1/2 both being girls

2)1/2 both being boys

3)21/32

Step-by-step explanation:

1)Total no. of girls=20+25=45

Total no. if students=90

The probability of both being girls=45/90

=1/2

2)Total no. of boys=30+15=40

The probability of both being boys=45/90

=1/2

3)The probability of 1 boy & 1 girl=(1 boy of 10 A and 1 girl of 10 B)+(1 boy of 10 B and 1 girl of 10 A)

>The probability of 1 boy and 1 girl= (30/40×25/40)+(15/40×20/40)

>750/1600+300/1600

>1050/1600=21/32

The probability of one girl and one boy is 21/32

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