1) In each pair of polynomials given below, find the number to be sub-
tracted from the first to get a polynomial for which the second is a factor.
Find also the second factor of the polynomial got on subtracting the
number.
(1) x2 – 3x + 5, x - 4
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Step-by-step explanation:
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☆ In each pair of polynomials given below, find the number to be sub-
tracted from the first to get a polynomial for which the second is a factor.
Find also the second factor of the polynomial got on subtracting the
number.
⊙ x2 – 3x + 5, x - 4
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⊙ Expand (x−4)(x² − 3x+ 5) (x-4) (x² -3x + 5) by multiplying each term in the first expression by each term in the second expression.
5) by multiplying each term in the first expression by each term in the second expression.x⋅ x²+ x (−3x) + x⋅5 − 4x2 −4 (−3x) − 4⋅5x⋅x² + x(-3x)+ x⋅5 -4x2 -4(-3x)
implify terms.
⊙ Simplify each term.
⊙ Multiply xx by x²x2 by adding the exponents.
⊙ Multiply x by x².
⇒ x¹+² +x(−3x)+x⋅5−4x²−4(−3x)−4⋅5
⇒ Add 11 and 22.
⇒ x³+x(−3x)+x⋅5−4x²−4(−3x)−4⋅5x3+x(-3x)
+x⋅5-4x²-4(-3x)-4⋅5
⇒ Rewrite using the commutative property of
multiplication.
⇒ x³−3x⋅x+x⋅5−4x²−4(−3x
−4⋅5x3-3x⋅x+x⋅5-4x2-4(-3x)-4⋅5
⇒ Multiply xx by xx by adding the exponents.
⊙ Move x.
Move x.x³−3(x⋅x)+x⋅5−4x²−4(−3x)−4⋅5x3-3(x⋅x)
+x⋅5-4x2-4(-3x)-4⋅5
⊙ Multiply x by x.
Multiply x by x.x3−3x2+x⋅5−4x2−4(−3x)
−4⋅5x3-3x2+x⋅5-4x2-4(-3x)-4⋅5
⊙ Move 55 to the left of x.
Move 55 to the left of x.x3−3x2+5⋅x−4x2−4(−3x−4⋅5x3-3x2+5⋅x-4x2-4(-3x)-4⋅5.
⊙ Multiply −3-3 by −4-4.
Multiply −3-3 by −4-4.x3−3x2+5x−4x2+12x−4⋅5x3-3x2+5x-4x2+12x-4⋅5
⊙ Multiply −4-4 by 55.
Multiply −4-4 by 55.x3−3x2+5x−4x2+12x−20x3-3x2+5x-4x2+12x-20
Multiply −4-4 by 55.x3−3x2+5x−4x2+12x−20x3-3x2+5x-4x2+12x-20Simplify by adding terms.
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