Question

1. In fig. 1, ABC
SECTION-A
5x1=5 Marks
90° and Pis the mid point of AC. Find the length of AP given that AB=3cm and BC = 4cm.
P
3cm
B
4cm
fig. 1
s.​

Answer 1

Answer:

Length of AP = 2.5cm

Step-by-step explanation:

AC = 5cm (By Hypotenuse theorem)

P is the midpoint of AC i.e P divides AC in two equal part.

So , AP = 2.5cm

Answer 2

Answer:

2.5

Step-by-step explanation:

By Pythagoras theorem,

AB²+BC² = AC²

(3)² + (4)² = AC²

9 + 16 = AC²

25 = AC²

=>. AC = 5

AC = AP + PC

Given that P is the pid point of AC.

=>. AP = PC

So,

AC = AP + PC

5 = AP + PC

5 = AP + AP

5. = 2 (AP)

=> AP = 5/2

AP = 2.5