1. In Fig. 15.13, ABC is an isosceles right angled triangle
and DEFG is a rectangle. If AD = AE = 3 cm and
DB = EC = 4 cm, find the area of the shaded region.
Answers
Answered by
2
ANSWER
△ABC is a right angled triangle. So, by Pythagoras theorem
AC2=AB2+BC2=72+72=98
∴AC=98=72 cm
Arc A−B−C is a semicircle. ∴AC=72 cm is the diameter of the semicircle.
Area of the shaded portion = Area of semi-circle (A−B−C)− Area of △ABC
=21×4πd2−21×AB×BC
=2×7×422×98−27×7
=14 cm2
Similar questions