Question

1. In Fig. 6.13, lines AB and CD intersect at 0. If
ZAOC + Z BOE = 70° and Z BOD = 40°, find
BOE and reflex 2 COE.
70
А
8
Fig. 6.13​

Answer 1

Answer:

Z BOE = 30° and reflex Z COE = 250°

Explanation:

so first Given

Z AOC+Z BOE = 70°

Z BOD = 40°

to proove

Z BOE

reflex 2 Z COE

proof

1• Z BOD = Z AOC = 40° (vertically opposite angles)

so, Z AOC+ Z BOE = 70°

40° + Z BOE = 70°

Z BOE = 70°-40°

Z BOE =30°. (first answer)

2• now, Z AOC + Z BOE + Z COE = 180° (linear pair)

70°+ Z COE = 180°

Z COE = 180°-70°

Z COE = 110°

now reflex Z COE = 360°-110°

reflex Z COE = 250° ( second answer)

hope it helps you very much

Answer 2

Question :-

In figure, lines AB and CD intersect at 0. If ∠AOC + ∠BOE = 70° and ∠BOD = 40°, find ∠BOE and reflex ∠COE.

Answer :-

Since AB is a straight line,

∴ ∠AOC + ∠COE + ∠EOB = 180°

or (∠AOC + ∠BOE) + ∠COE = 180° or 70° + ∠COE = 180° [ ∵∠AOC + ∠BOE = 70° (Given)]

or ∠COE = 180° – 70° = 110°

∴ Reflex ∠COE = 360° – 110° = 250°

Also, AB and CD intersect at O.

∴∠COA = ∠BOD [Vertically opposite angles]

But ∠BOD = 40° [Given]

∴ ∠COA = 40°

Also, ∠AOC + ∠BOE = 70°

∴ 40° + ∠BOE = 70° or ∠BOE = 70° -40° = 30°

Thus, ∠BOE = 30° and reflex ∠COE = 250°.

Plz mrk as brainliest ❤