1.In figure 7.43, A is the centre of the circle.angle ABC=45% and AC =7√2 cm .Find the area of segment BXC??!
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Area of Shaded Portion::
area of sector- area of triangle
AB = AC (Radius)
therefore ang ABC = ang ACB
THEREFORE ang BAC = 90
Area of sector= pi x (r)^2 x (Theta)/360
= (22/7)(7√2)^2 x(90/360)
= (22/7)(98)(1/4)
by solving
Area = 77cm^2
area of triangle
right angle triangle
Pythagoras theorem
AB^2 + AC^2 = BC^2
(7√2)^2 + (7√2)^2 = BC^2
2x 98 = BC^2
BC^2 = 196
BC = 14
area = (1/2) Base x Height
= (1/2) (7√2)(7√2)
= 49
Area of Shaded = 77-49= 28cm^2
area of sector- area of triangle
AB = AC (Radius)
therefore ang ABC = ang ACB
THEREFORE ang BAC = 90
Area of sector= pi x (r)^2 x (Theta)/360
= (22/7)(7√2)^2 x(90/360)
= (22/7)(98)(1/4)
by solving
Area = 77cm^2
area of triangle
right angle triangle
Pythagoras theorem
AB^2 + AC^2 = BC^2
(7√2)^2 + (7√2)^2 = BC^2
2x 98 = BC^2
BC^2 = 196
BC = 14
area = (1/2) Base x Height
= (1/2) (7√2)(7√2)
= 49
Area of Shaded = 77-49= 28cm^2
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