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In figure, if angle BAC = 90° and AD perpendicular BC. Then,
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In a triangle ABC, angle BAC = 90 degree and AD is perpendicular to BC . Then which one is true and why? :- BD.CD = BC2. BD.CD = AD2. AB.AC = BC2.
Step-by-step explanation:In Triangle ABC, angle BAC = 90 degree and AD is perpendicular to BC
Given in the question a perpendicular is drawn AD on BC from angle BAC which is 90 degree
So, these two triangles ABD and CAD are similar
By Corresponding part of Similar Triangles (CPST),
If two triangles are similar, then the ratio of the area of both triangles is proportional to the square of the ratio of their corresponding sides.
This proves that the ratio of areas of two similar triangles is proportional to the squares of the corresponding sides of both the triangles.
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