Math, asked by smrithimettimi, 9 months ago

1. In how many years will ₹4000 amount to ₹5324 at 10% p.a.Compounded annually?

2. What sum of money will amount to ₹2508.80 at 12% p.a. compounded annually in two years of time?

3. At what rate of compound interest p.a. Will ₹1250 amount two ₹1800 in two years?

4. The difference between the compound and simple interest on a certain sum at 12% per annum for two years is ₹90. Find the principal?

5. A sum of money invested at compound interest of 8% p.a. compounded annually amounted to ₹7290 two years. Find the sum invested.

6. An investment at the rate of 18% p.a. compounded annually amounted to ₹4177.20 in two years. What was the sum invested?

Answers

Answered by SonalRamteke
10

Answer:

  1. So in 3- years ₹4,000 will give an amount of ₹5324 at a rate of 10% interest compounded annually.
  2. 2508.80, R = 12%, Time = 2 years. P = 2000.63. Therefore, Sum of money = ~2000.
  3. Step-by-step explanation: Here is your answer... Rate = ? Therefore, the rate is
  4. The difference between the compound interest and the simple interest on a certain sum at 12% p.a. for two years is Rs. 90. ... As the simple interest for a year = 750 @ 12% p.a., the principal =750/0.12 = Rs. 6250.
  5. Let the principal be 'x'
  6. We know,
  7. A=P(1+(R/100))^n
  8. 7290=x(1+0.08)^2
  9. 7290=x(1.08)^2
  10. 7290=1.1664x
  11. x=7290/1.1664
  12. x=6250
  13. Thus, the principal is Rs. 6250

Answer:6

3000

Step-by-step explanation:

Given An investment at the rate of 18% compounded anually amounted to rs 4177.20 in two years.

We know that

A = p(1 + r/100)^

4177.20 = p(1 + 18/100)^2

4177.20 = p(118 /100)^2

P(1.3924) = 4177.20

P = rs 3000

The sum invested is rs 3000

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