Math, asked by aman6394130, 2 months ago

1) In parallelogram ABCD, if < A = (3x+12)°, < B = (2x-32)°then find the value of x and then find the measure of of angle C and angle D.​

Answers

Answered by theju23
1

Answer:

93.6°= c

86.4°= d

Step-by-step explanation:

Given

a = (3x+12)°

b = (2x-32)°

a+b = 180° (adjacent angles of a parallelogram are supplementary)

= (3x+12)°+(2x+32)° = 180°

= (3x+12+2x+32)°= 180°

= (5x+44)° = 180°

= 5x = 180°-44°

= 5x = 136°

= x = 136°/5

= x = 27.2°

a=c

b=d

( Opposite angles of a parallelogram are equal)

(3x+12)°= c

= {3(27.2)+12}°= c

= 93.6°= c

(2x+32)°= d

= {2(27.2)+32}°= d

= 86.4°= d

Hope it helps!!

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